10 questions · Form 4 Physics Bab 2: Force and Motion I
10 questions · plays in fullscreen
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. An object in free fall near Earth's surface accelerates at approximately 9.81 m s⁻². This means that during every second of fall:
Answer: B
Acceleration of 9.81 m s⁻² means velocity increases by 9.81 m s⁻¹ every second.
2. A soccer player kicks a 0.5 kg stationary ball, giving it a speed of 20 m s⁻¹. If the foot stays in contact with the ball for 0.05 s, calculate the average force exerted on the ball.
Answer: C
F = mv - mut = 0.5 × 20 - 00.05 = 100.05 = 200 N.
3. Car bumpers and crumple zones are designed to collapse during a collision. How does this protect passengers?
Answer: B
Extending impact time t reduces the impulsive force F (since F = Δpt).
4. In an elastic collision between two objects, which of the following quantities are conserved?
Answer: C
In elastic collisions, both total momentum and total kinetic energy are conserved.
5. Which of the following actions increases the impulsive force in an activity?
Answer: C
A hard wooden bat decreases contact duration t, resulting in a significantly higher impulsive force F.
6. Calculate the weight of an astronaut of mass 70 kg on the Moon, where gravitational field strength g = 1.6 m s⁻².
Answer: A
W = mg = 70 kg × 1.6 m s⁻² = 112 N.
7. A trolley of mass 2 kg moving at 4 m s⁻¹ collides and sticks to a stationary trolley of mass 2 kg. Find their common velocity after collision.
Answer: B
Inelastic collision: m₁u₁ + m₂u₂ = (m₁ + m₂)v => (2×4) + (2×0) = (2+2)v => 8 = 4v => v = 2.0 m s⁻¹.
8. If a feather and a heavy steel ball are dropped simultaneously from the same height in a vacuum, which statement is true?
Answer: C
In a vacuum, air resistance is absent. All objects undergo free fall with the same gravitational acceleration g.
9. A stone is thrown vertically upwards with an initial velocity of 15 m s⁻¹. Assuming g = 9.81 m s⁻² and neglecting air resistance, what is its velocity at the maximum height?
Answer: C
At maximum height, an object momentarily comes to a complete stop, so its velocity v = 0 m s⁻¹.
10. What is the momentum of a 1200 kg car traveling at a constant velocity of 15 m s⁻¹?
Answer: C
Momentum p = mv = 1200 kg × 15 m s⁻¹ = 18,000 kg m s⁻¹.